x^2+10=3x-17

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Solution for x^2+10=3x-17 equation: 



x^2+10=3x-17

We move all terms to the left:

x^2+10-(3x-17)=0

We get rid of parentheses

x^2-3x+17+10=0

We add all the numbers together, and all the variables

x^2-3x+27=0

a = 1; b = -3; c = +27;
Δ = b2-4ac
Δ = -32-4·1·27
Δ = -99
Delta is less than zero, so there is no solution for the equation

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